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0=3x^2+18x-220
We move all terms to the left:
0-(3x^2+18x-220)=0
We add all the numbers together, and all the variables
-(3x^2+18x-220)=0
We get rid of parentheses
-3x^2-18x+220=0
a = -3; b = -18; c = +220;
Δ = b2-4ac
Δ = -182-4·(-3)·220
Δ = 2964
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2964}=\sqrt{4*741}=\sqrt{4}*\sqrt{741}=2\sqrt{741}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{741}}{2*-3}=\frac{18-2\sqrt{741}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{741}}{2*-3}=\frac{18+2\sqrt{741}}{-6} $
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